PLEASE HELP ASAP In a closed system with no friction, a red sphere of 2.5 kg stands stationary. A blue sphere with a mass of 5.8 kg approaches the first sphere with a speed of 4.1 m/s. The two collide. After the collision, the blue sphere begins moving forward with a speed of 1.3 m/s. What is the velocity of the red sphere after the collision?

m1 = the mass of the blue sphere = 5.8 kg

m2 = the mass of the red sphere = 2.5 kg

v1 = initial velocity of the blue sphere before the collision = 4.1 m/s

v2 = initial velocity of the red sphere before the collision = 0 m/s

v'1 = final velocity of the blue sphere after the collision = 1.3 m/s

v'2 = final velocity of the red sphere after the collision = ?

using conservation of momentum

m1v1 + m2v2 = m1v'1 + m2v'2

(5.8) (4.1) + (2.5) (0) = (5.8) (1.3) + (2.5) (v'2)

23.78 = 7.54 + (2.5) (v'2)

-7.54    -7.54

16.24 = (2.5) v'2

 2.5         2.5

v'2 = 6.5

Explanation:

answer: option c. i.e. electric current flowing “downhill” from the negative electrode to the positive electrode in a battery

explanation:

the water analogy to the circuits define the pipes (water flows) to the electric current. now, we know that the electric current flows from the positive terminal to the circuit (as shown in the diagram attached).

hence, option c is the correct answer.

in physics zero. in muscle fatigue could be high