g You are following 25 m behind another car on the highway while talking on the cell phone. Both you and the other car initially have a constant speed of 110 km/hr. You being to argue with the person on the phone and become distracted from the road for 2 seconds. At the beginning of that two seconds, the other car sees something in the road ahead and begins to break hard, at 5 m/s2 . (a) How far apart are the two cars when your attention returns to the road

Δx = 10 m

Explanation:

For this problem we can calculate the distance traveled by each car in the time of 2 s

let's reduce the speed to the SI system

v = 110 km / h (1000m / 1 km) (1 h / 3600 s) = 30.556 m / s

Cart 1

this car has constant speed

            v = x₁ / t

            x₁ = v t

            x₁ = 30,556  2

            x₁ = 61.11 m

This car is that of the person with the cell phone

Cart 2

this car has an acceleration of a = 5 m / s²

            x₂ = v₀ t - ½ a t²

            x₂ = 30,556 2 - ½ 5 2²

            x₂ = 51,112 m

The difference in distance between the two vehicles is

            Δx = x₁ - x₂

            Δx = 61.11 - 51.11

            Δx = 10 m

reserve is the answer

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force