Two cars - Car A and Car B - drive in the same direction down a street. Car B is traveling at 30 m/s. Car A is traveling 20 m/s. Imagine that you're sitting inside Car A and Car B passes you. What is the velocity of Car B relative to you? Don't forget UNITS.

Special care would be an answer

C. the electric current passes from the slip rings, through the brushes, and to the collection device.

The figure is missing but we can answer anyway.the correct answer is "releasing the string". in fact, when the person is holding the bow and the arrow, the kinetic energy of the arrow is still zero (because the arrow is not moving). the moment the arrow is released, it acquires a velocity v, so its kinetic energy will become different from zero: where m is the mass of the arrow and v its velocity.  all the other options, instead, do not increase the kinetic energy of the system: -  pulling farther back on the string : this will just increase the elastic potential energy of the system-  holding the arrow higher: this will increase the gravitational potential energy of the system (which is given by u=mgh, where h is the height above the ground)-  decreasing the mass of the arrow: this will decrease the gravitational potential energy of the system (which is given by u=mgh, where m is the mass)