The near and far points of a person are at 40 cm and 200 cm respectively. He uses a lens for reading at 25 cm distance. The maximum distance clearly visible with lens is

225 cm

Explanation:

Given that the near ( the minimum distance visible to a person) and far points ( the maximum distance visible to a person) of a person are at 40 cm and 200 cm respectively.

If he uses a lens for reading at 25 cm distance, The maximum distance which is clearly visible with lens will be achieved by adding the far point of the person to 25 cm. That is,

The maximum distance = 25 + 200 = 225 cm

Therefore, the maximum distance clearly visible with lens is 225 cm.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

i need with 1.3.2 investigate cycling o2 and co2 apex

we need to see it