In each of the parts of this question, a nucleus undergoes a nuclear decay. Determine the resulting nucleus in each case. Part A
227/89 Ac undergoes alpha decay. Determine the resulting nucleus.
For example, if the resulting nucleus is 40/20 Ca enter ^40_20Ca.
Part B
211/83 Bi undergoes beta-minus decay. Determine the resulting nucleus.
For example, if the resulting nucleus is 40/20 Ca enter ^40_20Ca.
Part C
22/11 Na undergoes beta-plus decay. Determine the resulting nucleus.
For example, if the resulting nucleus is 40/20 Ca enter ^40_20Ca.
Part D
98/43 Tc undergoes gamma decay. Determine the resulting nucleus.
Enter your answer in the space below. For example, if the resulting nucleus is 40/20 Ca enter ^40_20Ca.

(A). The resulting nucleus is Fr.

(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

Explanation:

Given that,

A nucleus undergoes a nuclear decay.

(A). In alpha decay,

We know that,

When the nucleus emit alpha particle then atomic mass of particle reduce by 4 and atomic number reduce by 2.

We need to calculate the resulting nucleus

Using given data

The resulting nucleus is Fr.

(B). In beta-minus decay,

We know that,

When the nucleus emit beta- minus particle then atomic mass of particle is same and atomic number increase by 1.

We need to calculate the resulting nucleus

Using given data

The resulting nucleus is Po.

(C). In beta-plus decay,

We know that,

When the nucleus emit beta- plus particle then atomic mass of particle is same and atomic number decrease by 1.

We need to calculate the resulting nucleus

Using given data

The resulting nucleus is Ne.

(D). In gamma decay,

We know that,

When the nucleus emit gamma particle then atomic mass and atomic number of particle is same.

We need to calculate the resulting nucleus

Using given data

The resulting nucleus is Tc.

Hence, (A). The resulting nucleus is Fr.

(B). The resulting nucleus is Po.

(C). The resulting nucleus is Ne

(D). The resulting nucleus is Tc.

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation:

amplitude

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