An electric current of 200 A is passed through a stainless steel wire having a radius R of 0.001268 m. The wire is L = 0.91 m long and has a resistance R of 0.126 Ohm. The outer surface temperature Tw is held at 422.1 K. The average thermal conductivity is K = 22.5 W/mK. Calculate the center temperature. Power = I^2R (Watts) Where I = current in nmps and R = Resistance in ohms I^2R (Watts) = q pi(Radius)^2L

The value is  

Explanation:

From the question we are told that  

   The  current is  

   The radius is  

   The  length of the wire is  \

    The  resistance is  

    The  outer surface temperature is  

    The average thermal conductivity is  

Generally the heat generated in the stainless steel wire is mathematically represented as  

=>  

=>  

Generally the middle temperature is mathematically represented as

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explanation:

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