If your friend drops a chocolate bar to you from a height of 5.0 m above your hands, (a) How long would it take you to catch it? Use Eq. 2.

D=1/2 gt squared

Explanation:

Using the equation of motion S = ut+1/2gt² to solve the problem where;

u is the initial velocity of the chocolate = 0m/s

t is the time taken

g is the acceleration due to gravity = 9.81m/s²

S is the height of fall = 5.0m

Substituting the given parameter into the formula to get the time t we have;

5 = 0(t)+1/2(9.81)t²

5 = 4.905t²

t² = 5/4.905

t² = 1.019

t = √1.019

t = 1.009 secs

Hence it will take 1.01 secs for me to catch the chocolate bar

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