What is the magnitude of the acceleration of an electron that is 1.3 cm from the center of the bead?

Complete Question

A small plastic bead has been charged to  15nC. What is the magnitude of the acceleration of an electron that is 1.3 cm from the center of the bead?

The  acceleration is  

Explanation:

From the question we are told that

    The charge on the bead is  

     The  distance of the electron from the center of the bead is

Generally the force between the electron and the bead is  mathematically represented as

Here e is the charge on an electron with value  

        k is  the coulombs constant with value  

Mathematically

Here M is the mass of an electron with value  

So

=>  

=>    

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

the answer would be   dignified - apex