A particle has a velocity of v = 4 m/s and acceleration a = 10 m/s2. What is the distance traveled in 1 sec?

The distance traveled by the particle after 1 second is 9m.

Explanation:

Given;

velocity of the particle, v = 4 m/s

acceleration of the particle, a = 10 m/s²

time of motion of the particle, t = 1 second

distance traveled by the particle, d = ?

The distance traveled by the particle is given by;

d = vt + ¹/₂at²

d = (4 x 1) + ¹/₂(10)(1)²

d = 9 m

Therefore, the distance traveled by the particle after 1 second is 9m.

the answer is a)

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