A typical atom has a diameter of about 1.32 x 10-10 m. A) What is this in inches?
B) How many atoms are there along a 21.0cm line?

A) The value of the diameter in inches is 5.19685 × 10⁻⁹ inches

B)  There are 1,590,909,091 atoms on a 21.0cm line

Explanation:

A) To determine what its diameter is in inches

We will convert 1.32 × 10⁻¹⁰ m to inches

First convert this to centimeters (cm)

1.32 × 10⁻¹⁰m = 1.32 × 10⁻¹⁰ × 10² cm

=  1.32 × 10⁻⁸cm

Now, since 1 inch = 2.54 cm

∴ 1 cm = inches

If  1 cm = inches

Then 1.32 × 10⁻⁸ cm will be

1.32 × 10⁻⁸ × inches

= 5.19685 × 10⁻⁹ inches

This is the value of the diameter in inches

B) For the number of atoms on a 21.0cm line

The diameter of 1 atom is 1.32 × 10⁻¹⁰m

1.32 × 10⁻¹⁰m = 1.32 × 10⁻⁸cm

Hence, on a 21.0 cm line, we will have

(21.0 / 1.32 × 10⁻⁸) atoms

= 1590909091 atoms

Hence, there are 1,590,909,091 atoms on a 21.0cm line

the answer is to check all of them! they all apply well at least i think so!

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.