A hiker caught in a rainstorm absorbs 1.00 L of water in her clothing. If it is windy so that the water evaporates quickly at 20 ∘C, how much heat is required for this process?

2260000 J

Explanation:

From the question,

Q = ml Equation 1.

Where Q = Heat, m = mass of water, l = specific latent heat of vaporization.

But we can get the mass o water using the formula of density.

D = m/v Equation 2

Where D = density of water, v = volume of water.

make m the subject of the formula in equation 2

m = D×v Equation 3

Substitute equation 3 into equation 1

Q = D×v×l Equation 4

Given: v = 1.00 L = 0.001 m³.

Constant: l = 226000 J/kg, D = 1000 kg/m³

Substitute these values into equation 4

Q = 0.001(2260000)(1000)

Q = 2260000 J

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach