Se suelta una piedra cerca de la superficie lunar y cae libremente durante 7 segundos. La aceleración de la gravedad lunar es de 1,6 m/s² ¿qué velocidad alcanzará?

v = 11.2 m/s

Explanation:

A stone is dropped near the lunar surface and falls freely for 7 seconds. The acceleration of lunar gravity is 1.6 m / s², what speed will it reach?

Given that,

The acceleration due to the gravity of lunar gravity is 1.6 m/s²

A stone is dropped near the lunar surface and falls freely for 7 seconds.

We need to find the speed with which it reach.

The initial velocity of the stone will be 0 as it was at rest.

Using equation of kinematics v=u+at

So, the stone will reach with a speed of 11.2 m/s

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.