A skier traveling on a plane stretch of snow reaches the foot of a steady upward 17.5° inclined hill and glides 15.8 m up the slpe before coming to rest. If the average coefficient of kinetic friction is 0.47, how fast was the skier travelling at the bottom of the hill? Include a free body diagram in your complete solution.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

This question is incomplete and not physics but i'm  willing to if you can give a better question

Ithink it’s b hope it