Super fine 40-gauge copper wire has a diameter of only 0.080mm and weighs only 44.5/gkm. Suppose a spool of 40-gauge wire weighs 570.g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

mount of wire used=12.808989 Km

Amount of wire used=12808.989 m

Explanation:

Given Data:

Diameter of wire=d=0.080 mm=0.00008 m

Weight of wire per unit length=44.5 g/km

Spool weighs=M=570 g

Required:

Amount of wire used=L=?

Solution:

Formula is:

The above expression is mathematical model of finding how much wire is used. just put the Value of M we will get the answer.

Amount of wire used=12.808989 Km

Amount of wire used=12808.989 m

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

i believe the answer is electric potential.

explanation: