a helicopter is ascending vertically with a speed of 5.20 m/s with package of negligible size attached to the bottom of the helicopter, when the helicopter is 125 m above the ground the package is released and the helicopter continues to ascend at its same speed. air resistance is negligible in this problem.(a)what is the displacement of the helicopter 5 seconds after the package has been released?(b)what is the displacement of the package 5.0 seconds after it has been released?(c)how far apart are the bottom of the helicopter and the package after 5.0 seconds?

choosing tennis and golf balls is your inde choice.

their mass and volume are dep

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.