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7. Option D. 8.4×10¯⁴ m/s North.

8. Option B. 2 m/s

Explanation:

7. Determination of the speed of the snail.

The following data were obtained from the question:

Distance travalled (d) = 15 m

Time (t) = 300 mins

Speed (S) =?

Next, we shall convert 300 mins to secs. This can be obtained as follow:

1 min = 60 secs

Therefore,

300 mins = 300 × 60 = 18000 secs

Finally, we shall determine the speed of the snail as follow:

Distance travalled (d) = 15 m

Time (t) = 18000 secs

Speed (S) =?

Speed = Distance travelled /time

Speed = 15 / 18000

Speed = 8.3×10¯⁴ m/s

Since the snail travelled due north, the speed is therefore 8.3×10¯⁴ m/s North.

8. Determination of speed of the runner.

The following data were obtained from the question:

Distance travalled = 8 m

Time = 4 secs

Speed =?

Speed = Distance travalled / time

Speed = 8/4

Speed = 2 m/s

Therefore, the speed of the runner is 2 m/s.

the answer is c.)

explanation: