A ball starts from rest and undergoes uniform acceleration of 2.50m/s^2. What is the velocity of the ball 4s later?

Explanation:

Given:

v₀ = 0 m/s

a = 2.50 m/s²

t = 4 s

Find: v

v = at + v₀

v = (2.50 m/s²) (4 s) + 0 m/s

v = 10 m/s

The speed of the ball after 4s is 10 m/s.

There's not enough information to find its velocity. (We would need to know what direction it's moving.)

total distance/total time

(85 + 82)/(5+3)

167/8

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