A sack is pushed from rest , find the velocity after 6 m while moving at 10 m/s 2

The velocity after 6 m while moving at 10 m/s² ≈ 10.95 m/s

Explanation:

The given parameters are;

The given distance of the sack movement = 6 m

The acceleration, a of the sack = 10 m/s²

The velocity of the is given from the relation;

v² = u² + 2×a×s

Where;

u =The initial velocity = 0

Which gives;

v² = 2×a×s

v² = 2×10×6 - 120

v = √120 = 2·√30 m/s

The velocity after 6 m while moving at 10 m/s² is 2·√30 m/s or approximately equal to 10.95 m/s.

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