A newly discovered planet has a radius twice as large as earth's and a mass five times as large. What is the free-fall acceleration on its surface?

free-fall acceleration = 12.25 m/s²

Explanation:

Formula for free fall acceleration is given by the gravity equation;

g = Gm/r²

Where;

M is mass of the Earth

r is radius of the Earth

G is the gravitational constant

Now, that equation applies to the earth.

For this new planet, we are told that the mass = 5 × mass of earth

And radius = 2 × radius of earth.

Thus, free fall acceleration for this planet is;

g_p = G(5m)/(2r)²

g_p = (5/4)(Gm/r²)

Gravitational constant has a value of 6.674 × 10^(−11) N.m²/kg²

Mass of the earth = 5.972 × 10^(24) kg

Radius of the earth = 6378 km = 6378000

Thus;

g_p = (5/4)(6.674 × 10^(−11) × 5.972 × 10^(24))/(6378000²) = 12.25 m/s²

false

explanation:

boats, things on boats luggage are way more heavy then water.

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.