A particle with charge q and kinetic energy K travels in a uniform magnetic field of magnitude B. If the particle moves in a circular path of radius R, find expressions for: a. its speed
b. its mass.

Given that K.E is

1/2mv²

So to find speed v,

Make it subject

K.E= 1.2mv²

However radial force = magnetic force

So mv²/r= qvB

So v subject

V= 2K.E/ qBr that is speed

To find mass

K.E = 1/2mv²

Puy value of v

So KE= 1/2m(2K.E/qBr)

m= (qBr)/2K.E

That is mass

m = qbr/v

v = 2k/qbr

Explanation:

When a charged particle enters a magnetic field, it experiences a force that is always perpendicular to the velocity. This force provides a centripetal force, and thus, we have

qvb = mv²/r

if we make m the subject of the formula, we will have

m = qbr/v

Recall that the kinetic energy, KE = ½mv²

Now, let's make v² the subject of formula, we have

v² = 2K/m

now, we substitute for m from the equation we got earlier

v² = 2K / (qbr/v)

v² = 2Kv / qbr, if we simplify further, we have

v = 2k / qbr

Therefore, we can say that the expression for the mass and speed is respectively,

m = qbr/v

v = 2k/qbr

area of focus

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

not copied too! hope this !

joke:

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