A vertical scale on a spring balance reads from 0 to 220 N. The scale has a length of 15.0 cm from the 0 to 220 N reading. A fish hanging from the bottom of the spring oscillates vertically at a frequency of 2.70 Hz. Ignoring the mass of the spring, what is the mass m of the fish?

Mass of fish is 5.09Kg

Explanation:

First to find the spring constant K using

k = F/s

= 220/0.15 = 1466.7 N/m

So using the formula

T = 2π√(m/k)

f = 1/T = 1/2πx √(k/m)

f² x 4π²= k/m

So

m = k/(f² x π²)

m = 1466.7/(2.7² x 4π²)

m = 5.09 kg

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need to see circuit to get time constant