A charge (uniform linear density = 8.8 nC/m) lies on a string that is stretched along an x axis from x = 0 to x = 3.1 m. Determine the magnitude of the electric field at x = 5.2 m on the x axis.

answer= 73.1256

Explanation:

The electric charge linear density is equal to 8.8 x

the length of the string is 3.1m

The magnitude of the electric field at the length of the string equal to 5.2 meters can be calculated with the formula ;

- E = λ / 4πε₀ [  / α ( α +

Solution:

E =  8.8 x / 4πε₀ [ 3.1/ 5.2( 5.2 + 3.1) ]

= 1018.0995 [0.07183]

=  73.1256

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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