Physics, 12.08.2020 04:01 deedee2616
When a monochromatic light of wavelength 433 nm incident on a double slit of slit separation 6 µm, there are 5 interference fringes in its central maximum. How many interference fringes will be in the central maximum of a light of wavelength 632.9 nm for the same double slit?
Answers: 2
![\theta = sin^{-1} [\frac{5 * 433 *10^{-9}}{ 6 *10^{-6}} ]](/tpl/images/0718/0428/4e06e.png)
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When a monochromatic light of wavelength 433 nm incident on a double slit of slit separation 6 µm, t...
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