dos vehiculos salen al encuentro desde dos ciudades separadas por 300 km , con velocidades de 55km/h y 40 km/h , respectivamente . si el que circula a 40 km/h sale dos horas mas tarde , ¿ el tiempo que tardan en encontrarse ? ¿ la distancia recorrida por el primer auto al momento de encontrarse?

t = 4 h ,   x₁ = 220 km

Explanation:

We can solve this exercise using the uniform motion relations

for car 1 the distance traveled

                x₁ = v₁ t

for car 2 the distance traveled where we take the road that leaves 2 hours later

                x₂ = x₀ -v₂ (t-2)

at the point where they meet they are at the same distance

                x₁ = x₂

               v₁ t = x₀- v₂ (t-2)

               t (v₁ + v₂) = x₀ +2 v₂

               t = (x₀ + 2 v₂) / (v₁ + v₂)

let's calculate

              t = (300 +2 40) / (55 +40)

              t = 380/95

              t = 4 h

the distance traveled by the first car

              x₁ = v₁ t

              x₁ = 55 4

              x₁ = 220 km

second mirror gathers light from a faraway object and reflects it to another mirror. - a.

it is the second option.