A 3 kg rock is swung in a circular path and in a vertical plane on a 0.25 m length string. At the top of the path, the angular velocity is 11 rad/s. What is the tension in the string at that point

The tension in the string at that point is 90.75 N

Explanation:

Given;

mass of the object, m = 3 kg

length of string, r = 0.25 m

the angular velocity, ω = 11 rad/s

The tension on string can be equated to the centrifugal force on the object;

T = mω²r

Where;

T is the tension in the string

m is mass of the object

ω is the angular velocity

r is the radius of the circular path

T = 3 x (11)² x 0.25

T = 90.75 N

Therefore, the tension in the string at that point is 90.75 N

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