Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s. What is the velocity of car B after the collision?

V = 2.35m/s

Explanation:

(Ma x Ua) + (Mb x Ub) = (Ma x Mb)V

(281 x 2.82) + (209 x 1.72) = (281 + 209)V

(792.42) + (359.48) = (490)V

1151.9 = 490V

V = 1151.9/490 = 2.35m/s

V = 2.35m/s

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.