You can chew through very tough objects with your incisors because they exert a large force on the small area of a pointed tooth. What pressure in Pa can you create by exerting a force of 360 N with your tooth on an area of 1.08 mm2

3.33×10⁸ Pa

Explanation:

Pressure: This can be defined as the force acting normally (perpendicular) per unit area. The S.I unit of force is N/m² or Pa.

P = F/A Equation 1

Where F = force created with the tooth, A = Area.

Given: F = 360 N, A = 1.08 mm² = 1.08/1000000 = 1.08×10⁻⁶m.

Substitute this values into equation 1

P = 360/1.08×10⁻⁶

P = 3.33×10⁸ Pa.

Hence the pressure created = 3.33×10⁸ Pa

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not too sure thinking all accelerations are pointed down