A mass of 0.40 kg, hanging from a spring with a spring constant of 80 N/m, is set into an up-and-down simple harmonic motion. What is the speed of the mass when moving through a point at 0.05 m displacement

v = 1.22 m/s

Explanation:

Given that, Mass of the object, m = 0.4 kg

Spring constant of the spring, k = 80 N/m

The starting displacement from equilibrium is 0.10 m, or the amplitude, A = 0.1 m

To find, The speed of the mass when moving through the equilibrium point.

Displacement in the mass, y = 0.05

Solution, Let  is the angular frequency of the mass. It can be calculated as :

When the mass displaces from some position, the speed of the mass is given by : v = 1.22 m/s

So, the speed of the mass when moving through the equilibrium point is 1.22 m/s.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

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