When a boat is placed in liquid, two forces act on the boat. Gravity pulls the boat down with a force equal to the weight of the boat. Weight is measured in newtons (N). To calculate the weight of a boat, multiply its mass in grams by 0.00982. As the boat sinks into the liquid, the liquid pushes back. The force of the liquid pushing up on the boat is called the buoyant force.

Required:
How do gravity and the buoyant force affect a boat?

the fraction of submerged volume is equal to the ratio of the densities of the body between the density of the fluid.

Explanation:

This is a fluid mechanics problem, where as the boat is in equilibrium with the pushing force we can write Newton's second law

                  B- W = 0

                  B = W

the thrust force is equal to the weight of the liquid that is dislodged

                  B = ρ g V

we substitute

             ρ g V = m g

             V = m /ρ_fluid          1

we can write the mass of the pot as a function of its density

             ρ_body = m / V_body

            m = ρ_body  V_body

             V_fluid / V_body = ρ_body / ρ _fluid         2

Equations 1 and 2 are similar, although 2 is easier to analyze, the fraction of submerged volume is equal to the ratio of the densities of the body between the density of the fluid.

The effect appears the pot as if it had a lower apparent weight

where is the photo and the answer choices?