.- Un cuerpo es lanzado con una velocidad de 20 m/s, formando un ángulo con la horizontal de 50o, determinar el tiempo de vuelo, el alcance máximo y la altura máxima

- t = 3.12s

- x = 40.19m

- h_max = 11.97m

Explanation:

- In order to calculate the flight time of the body, you use the following formula:

        (1)

vo: initial speed  = 20m/s

g: gravitational acceleration = 9.8 m/s^2

θ: angle with the horizontal of the direction of the motion of the body = 50°

You replace the values of the parameters in the equation (1):

The flight time of the body is 3.12s

- The maximum range of the motion is given by:

where you have used the flight time.

The maximum horizontal distance traveled by the body us 40.19m

- The maximum height is:

             (2)

you replace the values of the parameters:

The maximum height is 11.97 m

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm