Please help. Basic. Brainliest will be given.

28.7 m at 46.9°

Explanation:

The x component of the displacement is:

x = 6 m cos 0° + 25 m cos 57°

x = 19.6 m

The y component of the displacement is:

y = 6 m sin 0° + 25 m sin 57°

y = 21.0 m

The total displacement is found with Pythagorean theorem:

d = √(x² + y²)

d = 28.7 m

And the direction is found with trig:

θ = tan⁻¹(y/x)

θ = 46.9°

Distance of displacement = 28.71 m

Angle of displacement = 46.91 degrees

Explanation:

convert all individual displacements to simple vectors.

6m east  -> <6,0>

25m at 57 -> <25cos57, 25sin57>

Total displacement = sum of two vectors

= <6+25cos57, 0+25sin57>

=<19.62, 20.97>

Magnitude of displacement

= sqrt(19.62^2+20.97^2)

= 28.71

Direction of displacement

= atan2(20.97,19.62)

= 46.91 degrees

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s