A Carnot engine operates between a high temperature reservoir at 435 K and a river with water at 280 K. If it absorbs 3700 J of heat each cycle, how much work per cycle does it perform?

The work done by the carnot engine per cycle is 1318.31 J

Explanation:

Given;

high temperature reservoir, Th = 435 k

temperature of river water, Tl = 280 k

heat energy absorbed per cycle, Q = 3700 J

Determine the work done per cycle is calculated as;

Where;

W is the work done

Q is the absolute heat absorbed per cycle

Tl is the temperature of the cold liquid

Th is the temperature of the hot reservoir

Therefore, the carnot engine operating at the given conditions, performs 1318.31 J work per cycle.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂