Physics, 16.07.2020 02:01 bernardhenderso4459

1. A sphere with a mass of 10 kg and radius of 0.5 m moves in free fall at sea level (where the air density is 1.22 kg/m3). If the object has a drag coefficient of 0.8, what is the object’s terminal velocity? What is the terminal velocity at an altitude of 5,000 m, where the air density is 0.736 kg/m3? Show all calculations in your answer.

Answers: 3

Show answers

Answers

Answer from: zee786

The value of terminal velocity of object is 7.99 m/s and the value of terminal velocity at an altitude of 5000 m is 10.30 m/s.

Given data:

The mass of sphere is, m = 10 kg.

The radius of sphere is, r = 0.5 m.

The density of air is, $\rho = 1.22 \;\rm kg/m^{3}$ .

The drag coefficient of object is, $C_{d}=0.8$ .

The altitude is, h = 5000 m.

The density of air at altitude is, $\rho' =0.736 \;\rm kg/m^{3}$ .

The mathematical expression for the terminal velocity of an object is,

$v_{t}=\sqrt\dfrac{2mg}{\rho \times A \times C_{d}}$

here,

g is the gravitational acceleration.

A is the area of sphere.

Solving as,

$v_{t}=\sqrt{\dfrac{2 \times 10 \times 9.8}{1.22 \times (4 \pi r^{2}) \times C_{d}}}\\\\\\v_{t}=\sqrt{\dfrac{2 \times 10 \times 9.8}{1.22 \times (4 \pi \times 0.5^{2}) \times 0.8}}\\\\\\\v_{t}=7.99 \;\rm m/s$

Now, the terminal velocity at the altitude of 5000 m is given as,

$v_{t}'=\sqrt\dfrac{2mg}{\rho' \times A \times C_{d}}$

Solving as,

$v_{t}'=\sqrt{\dfrac{2 \times 10 \times 9.8}{0.736 \times (4 \pi \times 0.5^{2}) \times 0.8}}\\\\\\v_{t}'=10.30 \;\rm m/s$

Thus, we can conclude that the value of terminal velocity of object is 7.99 m/s and the value of terminal velocity at an altitude of 5000 m is 10.30 m/s.

Learn more about the terminal velocity here:

link

Answer from: Rogeartest4

The terminal velocity at sea level is 7.99 m/s

The terminal velocity at an altitude of 5000 m is 10.298 m/s

Explanation:

mass of sphere m = 10 kg

radius of sphere r = 0.5 m

air density at sea level p = 1.22 kg/m^3

drag coefficient Cd = 0.8

terminal velocity = ?

Area of the sphere A = $4\pi r^{2}$ = 4 x 3.142 x $0.5^{2}$ = 3.142 m^2

terminal velocity is gotten from the relationship

$Vt = \sqrt{\frac{2mg}{pACd} }$

where g = acceleration due to gravity = 9.81 m/s^2

imputing values into the equation

$Vt = \sqrt{\frac{2*10*9.81}{1.22*3.142*0.8} }$ = 7.99 m/s

If at an altitude of 5000 m where air density = 0.736 kg/m^3, then we replace value of air density in the relationship as 0.736 kg/m^3

$Vt = \sqrt{\frac{2mg}{pACd} }$

$Vt = \sqrt{\frac{2*10*9.81}{0.736*3.142*0.8} }$ = 10.298 m/s

Answer from: Quest

This is what i found on google “according to the collision theory, the following criteria must be met in order for a chemical reaction to occur: molecules must collide with sufficient energy, known as the activation energy, so that chemical bonds can break. molecules must collide with the proper orientation.” i hope this information you.

Answer from: Quest

the results is a decrease in air temperature with an increase of altitude.

explanation:

Another question on Physics

Physics, 21.06.2019 21:50

Which of the following is a homogenous mixture? o a. a toy box filled with toys o b. blood o c. trail mix o d. spaghetti and meatballs submit

Answers: 2

Answer

Physics, 22.06.2019 21:00

The first law of thermodynamics states that heat added to a system is neither created nor destroyed but is as it changes into other forms of energy.

Answers: 1

Answer

Physics, 22.06.2019 23:50

The star nearest to our sun is proxima centauri, at a distance of 4.3 light-years from the sun. how far away, in km, is proxima centauri from the sun?

Answers: 3

Answer

Physics, 23.06.2019 00:30

Why does the equilibrium position of the spring change when a mass is added to the spring? will the mass oscillate around the new equilibrium position of the spring or the previous position without a mass attached to the spring? if the equilibrium position of the spring changes by 20 cm (assuming no initial mass) when a mass is added to the spring with constant 4.9 kg/s^2, what is the mass of the object attached to the spring?

Answers: 2

Answer

You know the right answer?

1. A sphere with a mass of 10 kg and radius of 0.5 m moves in free fall at sea level (where the air...

Questions