g At 4 ft. from a point source of gamma radiation the intensity is 158 mRem/hr. How far away would you have to move to decrease the intensity to 17 mRem/hr.? [I1/I2 = (D2)2/(D1)2] I1(D1)2 = I2(D2)2

You will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.

Explanation:

The distance can be calculated using the following equation:

Where:

I₁ = 158 mRem/h

I₂ = 17 mRem/h

D₁ = 4 ft.

D₂=?

Hence, the distance D₂ is:

Therefore, you will have to move 12.2 ft to decrease the initial intensity to 17 mRem/h.

I hope it helps you!

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

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