A 16-pound weight is attached to a spring stretching it 1.28 feet. Assuming that a damping force equal to 5 times the instantaneous velocity acts on the system. 1. State the differential equation describing the motion of this spring/mass system.
2. Find the real-valued general solution of this DE of motion for this spring/mass system (with arbitrary constants).
3. If the weight is released 5 feet below the equilibrium position with an initial downward velocity of 2 ftsec, clearly write the initial conditions (including units).
4. Solve for the solution of the IVP, showing all work.

By dividing you can find the answer

Is a  vector quantity  that refers to "the rate at which an object changes its position." imagine a person moving rapidly - one step forward and one step back - always returning to the original starting position. while this might result in a frenzy of activity, it would result in a zero velocity. because the person always returns to the original position, the motion would never result in a change in position. since velocity is defined as the rate at which the position changes, this motion results in zero velocity. if a person in motion wishes to maximize their velocity, then that person must make every effort to maximize the amount that they are displaced from their original position. every step must go into moving that person further from where he or she started. for certain, the person should never change directions and begin to return to the starting position.

Rain is pulled by gravity which is a non contact force