A 10 kg body is suspended by a rope is pulled by means of a horizontal force to make 60°
by rope to vertical. The horizontal force is
1) 10 kgwt
2) 30 kgwt
3) 10/3 kgwt 4) 30/3 kgwt

The correct option is;

3) 10·√3 kgwt

Explanation:

The parameters given are;

Mass of body, m = 10 kg

Direction of applied force = Horizontal

Angle of inclination of the rope with the vertical, θ = 60°

The component of the tension in the rope equivalent to the force is given by the relation;

T·sin(θ) = F

The component of the rope tension still under gravitational pull  is given by the relation;

T·cos(θ) = m·g

Therefore, we have;

Which gives;

Therefore;

F = tan(θ) × m×g

Where:

g = Acceleration due to gravity

tan(θ) = √3

m = 10 kg

∴ F = 10·√3 × g = 10·√3 kg-wt.

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by

the answer is c. the lower legs are levers, and the knees are fulcrums. the ankles hold the loads.