what is the maximum torque on a coil 5 cm x 12 cm, composed of 600 turns, when it is carrying a current of 10^-5 A in a uniform field of .1 T

3.6×10⁻⁶  Nm

Explanation:

From the question,

The expression for maximum torque is given as

τ = BANIEquation 1

where τ = maximum torque, B = magnetic field, A = Area of the coil, N = number of turns, I = current carried by the coil.

Given: B = 0.1 T, A = (5×12) = 60 cm² = 0.006 m², N = 600 turns, I = 10⁻⁵ A.

Substitute these values into equation 1

τ = 0.1(0.006)(600)(10⁻⁵)

τ = 3.6×10⁻⁶  Nm

answer; i believe that the correct answer is (d) a very small amount of mass

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.