Two barges, each with a displacement (mass) of 570 Mg, are loosely moored in calm water. A stunt driver starts his 1870-kg car from rest at A, drives along the deck, and leaves the end of the 15° ramp at a speed of 30 km/h relative to the barge and ramp. The driver successfully jumps the gap and brings his car to rest relative to barge 2 at B. Calculate the velocity v2 imparted to barge 2 just after the car has come to rest on the barge.

The velocity imparted to barge 2 just after the car has come to rest on the barge = 0.096 km/h

Explanation:

Mass of the two barges, = 570000 kg

Mass of the car,

The horizontal component of car velocity:

The driver brings his car to rest relative to barge 2 at B:

Applying the principle of conservation of momentum:

the first step is making objective observations.

they have to be based on a certain event and can be confirmed by others if it is right or not.

answer: strength i guess

explanation: