Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree celcius.

T = 27° C = 27 + 273 = 300 K
Bolzmann constant: k b = 1.38065 · 10^(-22) J/K
K = 3/2 kb T
K = 3/2 · 1.38065 · 10^(-22) J/K · 300 K = 6.212925 · 10^(-20) J

Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree Celsius.

In order to calculate the average translational kinetic energy of a nitrogen molecule at 27 degrees celcius we will have to use the following formula: Average Translational KE molecule = (3/2)*1.38*10^-23 J/K× T. First we convert the 27 degrees celsius to kelvin. Which should give you 300.15. Now we simply replace it in the formula and you should get 6.213104999999999e-21.

I hope it helps, Regards.

Velocity=total displacement/timefrom house to store is 500 from store to neighbor is 200 therefore total displacement=500+200=700metrestherefore,700metres/910seconds=0.8metres per second