A wave travels at a speed of 242 m/s. If the distance between crests is 0.11 V

m, what is the frequency of the wave? Use / =

A. 0.00045 Hz

B. 190 Hz

c. 27 Hz

D. 2200 Hz

The correct answer is D. 2200 Hz

Explanation:

The frequency of a wave is measured in hertz (Hz) and refers to how often a wave passes through a point during a specific time. This factor can be calculated if you divide the velocity of the wave by the wavelength (distance between crests) this means f (frequency) = v (velocity) / λ (wavelength).

f (frequency) =  242 m/s (velocity) / 0.11 (wavelegth)

f = 2200 Hz

According to this, the frequency of the wave, in this case, is 2200 Hz

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

higher potential

explanation:

because it is in a high speed so it must move into a of high potential