I NEED HELP PLEASE, THANKS! :) A 20.0 cm tall object is placed 50.0 cm in front of a convex mirror with a radius of curvature of 34.0 cm. Where will the image be located, and how tall will it be? Please show all work.

i = -12.7 cm; h =  5.07 cm

Explanation:

1. Find the focal length

The focal length of a concave spherical mirror is half of its radius of curvature.

f = ½r = ½ × 34.0 cm = 17.0 cm

2. Find the image distance

A convex mirror produces a virtual image behind the mirror, so the image distance is negative.

3. Find the image size

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

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