What can be done to double the power output of an object?

double the speed of the object.

Explanation:

From the definition of power, power is the rate at which work is done. That is,

Power P = Work done/time

But

Work done = force × distance

Work done = F×S

Substitute F × S for work done on power formula.

P = (F×S)/t

P = F × S/t

But S/t = velocity V

P = F × V

Since power P is proportional to speed V, to double the power output of an object, the speed V of the object must be doubled.

double speed

Explanation:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

momentum of soft ball three times less than baskey ball