A circular disk of radius 2.0 m rotates, starting from rest, with a constant angular acceleration of 20.0 rad/s2 . What is the tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s

The tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s is 40m/s²

The formula for calculating the tangential acceleration is expressed as:

Given the following parameters:

Substitute the given parameters into the formula;

Hence the tangential acceleration of a point on the edge of the disk at the instant that its angular speed is 1.0 rev/s is 40m/s²

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  a = 40 m / s²

Explanation:

This is a kinematics problem, where we must use both linear and angular and the relationship between them

we'll eat by reducing the angular velocity to units if

      w = 1.0 rev / s (2pi rad / 1 rev) = 2pi rad / s

they ask us for linear acceleration, we use the relationships between linear or angular variables

       a = α R

       a = 20  2

       a = 40 m / s²

c) up

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get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.