In a double-slit interference experiment you are asked to use laser light of different wavelengths and determine the separation between adjacent maxima. You observe that this separation is greatest when you illuminate the double slit with In a double-slit interference experiment you are asked to use laser light of different wavelengths and determine the separation between adjacent maxima. You observe that this separation is greatest when you illuminate the double slit with:.1. yellow light.2. red light.3. blue light.4. green light.5. The separation is the same for all wavelengths.

the separation of the interference maxima is directly proportional to the wavelength

the greatest separation must be obtained for the red light of

λ = 700

Explanation:

The double slit interference experiment is explained for the constructive interference case by the expression

           d sin θ = m λ

where d is the separation between the slits, θ at the angle of separation of the different maxima, λ the wavelength and m the order of interference.

In these experiments the angles are always very small, so if the observation screen is at a large distance and y is the distance between the maximums, we can use trigonometry

             tan θ = y / L

   as the angle is small we can also use

           tan θ = sin θ / cos θ = sin θ

when substituting we find

         sin θ = y / L

the contributory interference equation remains

          d y / L = m λ

          y = m (L / d) λ

the quantity in parentheses is constant, so the variation in the separation of the interference maxima is directly proportional to the wavelength

by which the greatest separation must be obtained for the red light of

λ = 700

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