Select the atoms that are likely to lose electrons to form cations: O A. Fluorine (F)
B. Magnesium (Mg)
O C. Sodium (Na)
D. Sulfur (S)

Magnesium and Sulfur

Explanation:

If you take a look at the periodic table, you would see that Fluorine and Sulfur are positioned in the P - block, so that it should be a non - metal. Respectively Magnesium and Sodium belong to the S - block, and are hence metals.

There are two approaches to solving this problem;

1. Take a look at the position of each elements and see how many steps they are to the nearest noble gas configuration. If they need have to go back steps they would tend to lose electrons, and form a cation.

2. Check the position of each element and note if it is a metal or nonmetal. Metals tend to lose electrons and form cations

I have already started on the second approach. Thus, it should be that Magnesium and Sulfur meet the requirements listed ( lose electrons, form cations )

hi i’m sorry to call us today so we will get back with y’all and we will have to do it haha omg was the day

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27