Two parallel, metal plates with separation distance d = 1.00 cm carry charges of equal magnitude but opposite sign. The plates are oriented horizontally. Assume the electric field between the plates is uniform, and it has a magnitude of 1,920 N/C. A charged particle with mass 2.00 â 10^â16 kg and charge 1.02 â 10%â6 C is projected from the center of the bottom negative plate with an initial speed of 1.07 â 10%5 m/s at an angle of 37.0° above the horizontal. Assume the plates are square with side length = 20.0 cm. Required:
a. Describe the trajectory of the particle.
b. Which plate does it strike?
c. Where does it strike, relative to its starting point?
d. What is the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b)?

We have that  the trajectory of the particle,The plate the particle strikes,Where it strikes, relative to its starting point and the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b) are as follows

From the question we have that

Distance

Magnitude  

Mass

Charge

initial speed

Angle

Length

a)

The Particle follow a Parabola trajectory through its travel as a Parabola Creates a Curved Plane and has its initial half side same as the final side.with the particle is a angle create on its elevation and depression

Parabola

b)

It strikes the Negative plate at a specific distance to be discovered in the C part of the Question

c)

We are tasked to determine where the particle strikes the plate.

Generally the equation for strike distance S  is mathematically given as

Where

Therefore

d)

Generally the equation for  the minimum Velocity  is mathematically given as

In conclusion

The trajectory of the particle,The plate the particle strikes,Where it strikes, relative to its starting point and the minimum initial speed (in m/s) the particle must have in order to change the answer to part (b) are as follows

For more information on this visit

link

g

Explanation:

i'm just gonna leave this comment here, so i can get a challange done-

explanation: