What is the energy of a photon with a frequency of 2.2 x 1016 Hz? Planck's constant is 6.63 x 10-34 Jos. O 1.5 x 10-17
8.8 x 10-17
O 1.5 10-16
O 8.8 10-16

1.5 × 10^-17

Explanation:

Given the following :

Frequency(f) = 2.2 × 10^16 Hz

Planck's constant(h) = 6.63 × 10^-34

The energy of a photon 'E' is given as the product of frequency and the planck's constant

E = hf

E = (6.63 × 10^-34) × (2.2 × 10^16)

E = 6.63 × 2.2 × 10^(-34 +16)

E = 14.586 × 10^-18

E = 1.4586 × 10^-17

E = 1.5 × 10-17 (2 S. F)

if the thermos has a vacuum innner, then heat through conv currents and conduction are reduced = vacuum flask

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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