An engine performs 17,640 J of work on a scooter. The scooter and riderhave a combined mass of 180 kg. If the scooter started at rest, what is the speed of the bike after the work is performed?

  14 m/s

Explanation:

We assume that all of the work performed is translated to kinetic energy:

  KE = 1/2mv² . . . . m represents mass

  v = √(2KE/m) . . . . m represents mass

  = √(2(17,640J/180 kg)) = √(196 m²/s²) . . . . m represents meters

  v = 14 m/s

The speed of the bike is about 14 meters per second.

explanation:

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dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.