A 2kg object is dropped from a height 10m. Calculate the speed of the object after it has fallen 5m, assuming there is no resistance. g= 10 N/kg

10m/s

Explanation:

Since there is no initial velocity as the object is dropped, you can write the following equation:

Now that you know how long the fall took, you can use another physics equation to find the velocity at that point.

Since there once again is no initial velocity, you can rewrite this as:

Hope this helps!

The kinetic energy the object has at any point during the fall is exactly the potential energy it lost by falling to that height.

Potential energy = (mass) · (gravity) · (height)

Change of potential energy = (mass) · (gravity) · (change of height)

Change of potential energy = (2 kg) · (10 m/s ) · (-5 m)

Change of potential energy = 100 Joules

Kinetic energy = (1/2) · (mass) · (speed²)

Kinetic energy = (1 kg) · (speed² )

100 J = (1 kg) · (speed²)

Speed² = (100 J) / (1 kg)

Speed² = (100 kg-m²/s²) / (1 kg)

Speed² = (100 m²/s²)

Speed = 10 m/s  

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation