3. The circuit below shows two outdoor lights, run by a battery. Four amps of current leave the battery. Explain how the current splits to go through both light
bulbs. Be as specific as you can.

The answer to your question is given below.

Explanation:

From the diagram given in the question, we can see that the bulbs are in parallel connection. This implies that different current will go through the bulb but the same voltage. But the resistance of each bulb is the same, therefore the same current current will go through them.

This can further be understood if we determine the current flowing through each bulb. This is illustrated below:

Voltage (V) = 30V

Resistant 1 (R1) = 15Ω

Current 1 (I1) =..?

V = I1R1

30 = I1 x 15

Divide both side by 15

I1 = 30/15

I1 = 2A.

Voltage (V) = 30V

Resistant 2 (R2) = 15Ω

Current 2 (I2) =..?

V = I2R2

30 = I2 x 15

Divide both side by 15

I2 = 30/15

I2 = 2A.

The overall current(I) in the circuit:

I = I1 + I2

I = 2 + 2 = 4A.

From the illustrations above, we can see that the same current will flow through each bulb as the will current split into two equal parts

well clustered together.

points close on a scatter diagram